# Maths item of the month

## Curriculum mapping

A list of Maths Items of the Month categorised by GCSE/A level topics can be seen at: Maths Items of the Month Curriculum mapping.

## Recent Maths Items of the Month

### November 2015

Three Line Whip

Construct an equilateral triangle with one vertex on each of 3 parallel lines using just a straight edge and a pair of compasses.

Try the problem on GeoGebraTube: http://tube.geogebra.org/m/1941917

### October 2015

AOB

The points A and B are on the curve *y*=*x*^{2} such that AOB is a right angle. What points A and B will give the smallest possible area for the triangle AOB?

### September 2015

Reciprocating lengths

Given a straight line that intersects the *x* and *y* axes at A and B and the curve *y*=1/*x* at C and D, does AD=BC?

### August 2015

Prime Number Days

The ISO standard for writing dates is YYYY-MM-DD: e.g. the 1^{st} August 2015 is 2015-08-01.

The 21^{st} August 2015 is a *Prime Number Day* because 20150821 is a prime number.

When will other Prime Number Days fall in 2015?

Will there ever be two consecutive Prime Number Days?

### July 2015

A match made in seven

Is it possible to arrange seven points in a plane so that any subset of three points will contain at least one pair that is exactly 1cm apart?

### June 2015

A couple of MEI Conference taster problems

**Problem solving at KS3&4 - 13:45-14:45 Saturday 27th June with Phil Chaffe**

Pattern 1:

Pattern 2:

What would the shaded area of pattern 3 be?

**Florence Nightingale - 09:00-10:00 Friday 26th June with Stella Dudzic**

*“The regulation allowance of raw spirit which a man may obtain at the canteen is no less than 18½ gallons per annum ; which is, I believe, three times the amount per individual which has raised Scotland, in the estimation
of economists, to the rank of being the most spirit-consuming nation in
Europe.”*

Florence Nightingale on the British army in India in *“How people may live and not die in India. London : Emily Faithful, 1863.”*

How does this compare to current drinking habits?

### May 2015

A couple of MEI Conference problems

The following problems appeared in MEI Conference sessions in 2014:

**1×1=2**

You are told that, when rounded to the nearest whole number, *x* and *y* are both 1. What is the probability that, to the nearest whole number, *xy* = 2 ?

**Paper folding a parabola**

Prove that the following steps will produce a parabola:

- Fold a piece of A4 paper in half long-ways (to create the y-axis) and draw this in with a pen.
- Mark a point on the fold a couple of inches from the bottom edge.
- Fold the bottom edge so that it goes through the point and is perpendicular to the vertical fold (to create the x-axis) and mark this with a pen.
- Make repeated folds so that the bottom edge goes through the point – these can be at any angle.

### April 2015

Consecutive Fibonacci Squares

The first few Fibonacci numbers are 1, 1, 2, 3, 5, 8, 13, 21, 34 ... (each number is the sum of the previous two numbers in the sequence and the first two numbers are both 1).

The sums of the squares of some consecutive Fibonacci numbers are given below:

1^{2} + 1^{2} = 2

3^{2} + 5^{2} = 34

13^{2} + 21^{2} = 610

Is the sum of the squares of consecutive Fibonacci numbers always a Fibonacci number?

### March 2015

4 points, 2 lengths

In how many ways can you arrange 4 distinct points in the plane so there are exactly two different distances amongst the 6 pairs?

e.g. if the four points are at the corners of a square then the four sides are the same length and the two diagonals are the same length.

### February 2015

1, 2, 3, 4

Find two quadratic functions f(*x*), g(*x*) so the equation f(g(*x*)) = 0 has the four roots *x* = 1, 2, 3, 4.

Is it possible to find three quadratic functions f(*x*), g(*x*), h(*x*) so the equation f(g(h(*x*))) = 0 has the eight roots *x* = 1, 2, 3, 4, 5, 6, 7, 8?

### January 2015

Happy 2015: A Triple of Triples

2015 is the product of 3 distinct primes: 5×13×31

2014 and 2013 are also the product 3 distinct primes.

Can you find a smaller triple (*n*, *n*+1, *n*+2) where *n*, *n*+1 and *n*+2 are all the product of 3 distinct primes?

Are there any quadruples (*n*, *n*+1, *n*+2, *n*+3) where *n*, *n*+1, *n*+2 and *n*+3 are all the product of 3 distinct primes?